Math, asked by krushi1527, 9 months ago

In an exam there were 2000 candidates, out of which 900 were boys and the rest were girls.if 32 percent of the boys and 38 percent of the girls passed, then find the total percent of failed candidates

Answers

Answered by Anonymous

Girls = 900, Boys = 1100

Passed = ( 38% of 1100 ) + ( 32% of 900)

= 418 + 288 = 706

Failed = 2000 - 706 = 1294

Failed % = [(1294/2000) x 100]% = 64.7%.

Answered by chandanbhardwaj330

Answer:

64.7

given

total no. of students=2000

no. of boys = 900

no. of girls =2000-900=1100

32%of boys are pass =900×32/100=288

38%of girls pass =1100×38/100=418

total no. of student pass =706

total no. of student who's fail =2000-706=1294

in percentage = 1294×100/2000=64.7

Previous Question

Next Question