Question

in an examination, 24% students failed in mathematics, 27% failed in english and 20% failed in both the subjects.

i) find the percentage of students who failed in one or both the subjects

ii) find the percentage of students who passed in both the subjects

iii) if 345 students passed in both the subjects, find the total number of students​

IF you answer my question I will mark as brainlist

Answer 1

n(A)=27,n(B)=24,n(A⋂B)=20

i) n(A⋃B)=27+24−20

=31%

ii) n(A⋃Bˉ)=100−31=69%

iii) 69% of x=414

⇒10069×x=414⇒x=414×100/69

=600

Answer 2

$\huge{ \color{t}{ \textsf{ \textbf{ \underline{ \underline{Answєr:}}}}}}$

●《Given》 :-

⟹Percentage of students failed in maths = 24 %

⟹Failed in english = 27%

⟹Failed in both subjects = 20%

i) Percentage of students who failed in one or both the subjects = 24 + 27 + 20

= 71%

ii) Percentage of students who passed in both the subjects = 100 - 71

= 29%

iii) Let the total students be x .

Pased students = 345

i.e. 9 % of x = 245

x = 245× 100/29

x = 844

● Total students = 844.

Hope it helps ✔✔