Question

In an examination, 48% students failed in hindi and 32% students in history, 20% students failed in both the subjects. If the number of students who passed the examination was 880, how many students appeared in the examination if the examination consisted only of these two subjects?

Answer 1

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Answer 2

The number of student appeared in examination is 2200.

Step-by-step explanation:

Let the number of student appeared in examination is x.

Given:

• 48% students failed in hindi and 32% students in history, 20% students failed in both the subjects.

Total number of student failed in examination is given by

$\rightarrow \: p(hindi \cup \: history) = p(hindi) + p(history) - p(hindi \cap \: history) \\ \rightarrow \: p(hindi \cup \: history) = 0.48x + 0.32x - 0.2x \\ \rightarrow \: p(hindi \cup \: history) =0.8x - 0.2x \\ \rightarrow \: p(hindi \cup \: history) = \: 0.6x$

The number of student who passed in examination is given by

$\rightarrow \: 880 = x - 0.6x \\ \rightarrow 0.4x = 880 \\ \rightarrow x = 2200$

The number of student appeared in examination is 2200.