Question

In an examination 49% student failed in english 36% failef in hindi while 50% failed in both if total no of passed student is 450 then how many student appearef in examination

Answer 1

$\huge\mathfrak\green{Holaa Mate}$

According to the formula,

Percentage of students passed in both the subjects

[100-(x+y-z)%]

[100-(49+36-15)%]

Let total number of students = x

According to the question,

$x \times 300 \div 100 = 450$

$x = 450 \div 30 \times 100 = 1500$

Total number of students = 1500 .

$\huge\mathfrak\orange{Hope it helps}$

Answer 2

According to the formula .

Percentage of students passed in both the subjects  

= [100 - (x + y - z)]%

= [100 - (49 + 36 - 15)]% = 30%

Let total number of students = N  

According to the question,

(N x 30)/100 = 450

⇒ N = (450/30) x 100 = 1500

∴ Total number of students = 1500