Math, asked by Samayu, 5 months ago

In an examination, 5% of the applicants were found ineligible and 85% of the eligible candidates
belonged to the general category. If 4275 candidates belonged to other categories, then how many
candidates applied for the examination?​

Answers

Answered by mashikhan419
10

Step-by-step explanation:

Let the number of candidates applied for examination =x

5% candidate found ineligible

so eligible candidate =100−5=95%

Total eligible candidate=

100

95x

As given 85% of the eligible candidates belonged to the general category

so the eligible candidates belonged to other categories =100−85=15%

Hence total candidate belongs to other categories

=

100

95x

×

100

15

As given total candidate belongs to other categories =4275

100

95x

×

100

15

=4275

⇒x=

95×15

4275×100×100

⇒x=30000

Answered by ps2628410
1

Step-by-step explanation:

Let the number of candidates applied for examination =x

5% candidate found ineligible

so eligible candidate =100−5=95%

Total eligible candidate=

100

95x

As given 85% of the eligible candidates belonged to the general category

so the eligible candidates belonged to other categories =100−85=15%

Hence total candidate belongs to other categories

=

100

95x

×

100

15

As given total candidate belongs to other categories =4275

100

95x

×

100

15

=4275

⇒x=

95×15

4275×100×100

⇒x=30000

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