Question

In an examination 5% of the applicants were found ineligible and 85% of eligible candidates belonged to the general category. If 4275 candidates belonged to the other categories, then how many candidates applied for the examination?​

Answer 1

Answer:

Let the number of candidates applied for examination =x

5% candidate found  ineligible 

so eligible candidate =100−5=95%

Total eligible candidate= 10095x

As given 85% of the eligible candidates belonged to the general category

so the eligible candidates belonged to other categories =100−85=15%

Hence total candidate belongs to other categories

=10095x×10015

As given total candidate belongs to other categories =4275

⇒10095x×10015=4275

⇒x=95×154275×100×100

⇒x=30000

Answer 2

Answer:

42750 candidates.

Step-by-step explanation:

Given,

• 5% ineligible applications
• 85% eligible applications
• 4275 other categories applications

To Find,

• Total applications.

Solution,

• Ineligible and eligible applications are (5%+85%)=90%
• Other categories applications are (100%-90%)=10%

Then,

$10\% = 4275 \\ 1\% = \frac{4275}{10} \\ 100\% = \frac{4275 \times 100}{10} \\ 42750$

Hence, 42750 candidates applied for the examination.

Hope this helps you!✌✌