in an examination 60% of examines failed in mathematics 55% failed in English and 24 failed in both subjects if none of the examination passed in both subjects find the number of examines who passed in mathematics only
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Answer:
n(M) = 60%
n(E)= 55%
n(M U E) =100% ( as none passed in both)
n(M U E) = n(M)+n(E)-n(M ∩ E)
or, 100=60+55-n(M ∩ E)
or, n(M ∩ E) = 15
now, 15% of total examines = 24
total examines = 24*100/15= 160
no of students who passed in math only =( 55-15)% of 160 = 40*160/100=64
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