Question

In an examination, 62% candidates passed in physics and 60% candidates passed in Mathematics. If 37% candidates passed in both these subjects, what percent of the candidates failed in both the subjects? A. 5% B. 20% C. 25% D. 15%

Answer 1

Answer:

Step-by-step explanation:

let the total number of candidates be x

students who passed in phy=62% of x=62x/100

students who passed in mathematics=60% of x=60x/100

students who passed in both the subjects=37% of x =37x/100

here,we have to just apply the set theorem

we know that n(AUB)= n(A)+n(B) -n(A∩B)

here n(A)=62x/100

        n(B)=60x/100

        n(A∩B)=37x/100

so AUB=(62x/100)+(60x/100)-(37x/100)=(62x+60x-37x)/100=85x/100

we know that AUB means A or B

that means the no. of students who passed in phy or maths=85x/100

that means the no of students who passed in at least one of the two subjects=85x/100

we know that the complement of AUB will be our required answer

that means the opposite of "students passing in atleast one subject" is

"students failing in both the subjects"

so that means no of students failing in both the subjects

=x-85x/100 = 15x/100 = 15 %of x

so the percentage of candidates who failed in both the subjects=15%

Hope this helps you

pls mark as brainliest

thanks :)