in an examination 80% students passed in english, 90% passed in mathematics and 75% in both english and mathematics. the number of student who failed in both subject is 45. draw a venn - diagram and find the total number of student
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So, we have n(A) = 80% of x = 80100×x
n(B) = 85% of x = 85100×x
Also, we are given that 75% students passed in both subjects. So, n (A∩B) = 75% of x = 75100×x
Now, we will use the property n(A∪B) = n(A) + n(B) - n(A∩B) to find the total students passed.
Therefore, n(A∪B) = 80x100 + 85x100 - 75x100 = 90x100 = 9x10
Total number of students passed = n (A∪B) = 9x10
So, students failed in both the subjects = total students – total number of students passed
Students failed = x - 9x10 = x10
But, according to the question, students failed = 40
Therefore, x10 = 40
⇒ x = 400
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