Question

In an examination 91 percent student passed if 18 student failed find how many students appeared in the examination

Answer 1

Given:

• Percentage of students passed = 91%.

• No. of students failed = 18.

To Find:

• Total no. of students appeared in the examination.

Solution:

let us suppose the total no. of students appeared in examination be x.

$:\implies\mathfrak{percentage \: of \: Failed \: Students = } \\ \\ \\ :\implies\mathfrak{ = 100 - 91} \\ \\ \\ \boxed{:\implies\mathfrak\red{Percentage \: of \: failed \: students = 9}}$

According to question,

$:\implies\mathfrak{9 \: of \: x = 18} \\ \\ \\ \\ \\ :\implies\mathfrak{ \frac{9}{100} \times x = 18} \\ \\ \\ \\ \\ :\implies\mathfrak{x = \frac{18 \times 100}{9} } \\ \\ \\ \\ \\ :\implies\mathfrak{x = \dfrac{\cancel{1800}}{\cancel{9}}} \\ \\ \\ \\ \\ :\implies\star \: {\underline{\boxed{\mathfrak{x = 200}}}}$

Thus,

• Total 200 students appeared in the examination.

Answer 2

Gıѵєη :

• Percentage of students passed in the examination = 91%
• Number of students failed in the examination = 18

Tσ Fıηd :

• Total number of students appeared the examination.

Sσłυтıση :

Percentage of students failed in the examination = 100% - 91%

$\implies{\underline{\sf{\orange{9\%}}}}$

Let the total number of students appeared the examination be a.

According to the question,

:$\implies{\sf{9 \%\:of a = 18}}$

:$\implies{\sf{ \dfrac{9}{100} \times a = 18}}$

:$\implies{\sf{ a = 18 \times \dfrac{100}{9}}}$

:$\implies{\sf{ a = \dfrac{18 \times 100}{9}}}$

:$\implies{\sf{ a = \dfrac{1800}{9}}}$

:$\implies{\boxed{\sf{\orange{ a = 200}}}}$

Therefore, the total number of students appeared the examination is 200.

And we are done! :D

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