Question

In an examination, 91% students passed
If 18 students failed, find how many
students appeared in the examination​

Answer 1

Given :-

• 91% students passed.
• If 18 students failed.

To Find :-

• How many students appeared in the examination.

Solution :-

Let students appeared in the examination be x

Students failed = 100% - 91% = 9%

No. of students failed = 9/100 × x = 18

x = 18 × 100/ 9

x = 2 × 100

x = 200

Hence, 200 students appeared in the examination.

Answer 2

Answer:

Total no. of students appeared in examination is 200.

Step-by-step explanation:

Solution

Let the total number of students be x.

When x ( the total no. of students ) is subtracted from 91% of x, it becomes 18.

Therefore,

x-(91% of x) = 18

➡️x-(91/100×x)=18

➡️x-91/100x=18

➡️100x-91x/100=18

➡️9x/100=18

➡️x=18×100/9

➡️x=200

Not sure with the answer

Let's check whether the answer is right or wrong.

Total no. of students appeared in examination = 200

So, 200-(91% of 200)

200-(91/100×200)

=200-182

=18

So the the total no. of students appeared in examination is 200.