Question

in an examination a candidate scores 25% of the maximum marks fails by 60 marks but another candidate secures 42% of maximum marks get 8 marks more than necessary for passing find the maximum marks and percentage necessary for passing

Answer 1

let max.marks be x

25% of x +60 = passing marks

x/4 + 60 = passing marks

NOW

ANOTHER CANDIDATE

42% of x = 8 + x/4 + 60( 8 + passing marks)

0.42x - 0.25x = 68



0.17x = 68

x = 6800/7 = 400

passing marks= x/4 +60 = 100 +60 = 160

% marks necessary = 160/400 ×100 = 40%