Question

In an examination , a candidate who scored 20% of the maximum marks fails by 40 marks another candidate who secures 45% of the maximum marks, gets 10 marks more than necessary for passing.​

Answer 1

Answer:

Total Marks = 200

Passing Marks = 80

Step-by-step explanation:

Let total marks be x

and passing marks be y

Student 1: 20% of x = y - 40

Student 2: 45% of x = y + 10

Student 1:

20% of x = y - 40

0.2x = y - 40

0.2x - y = -40 --------------eq.(i)

Student 2:

45% of x = y + 10

0.45x = y + 10

0.45x - y = 10 --------------eq.(ii)

On subtracting eq.(i) from eq.(ii)

0.45x - y = 10

0.20x - y = -40

- + + ( changing the signs)

_____________

0.25x = 50

25x/100 = 50

25x = 50 * 100

25x = 5000

x = 5000/25

{ x = 200 }

On putting the value x = 200 in eq.(i), we get passing marks;

0.2x - y = -40

0.2 * 200 - y = -40

40 - y = -40

y = 40 + 40

{ y = 40 }