In an examination a girl secures 42% and passes the examination by 7 marks, find maximum & minimum marks of the examination, if the cutoff is 40%.
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Total marks is 350 and pass marks is 140
Step-by-step explanation:
Marks Secured = 42% which is 7 more than Pass marks
Pass Percent= 40%
Let the total marks be x
So,according to the condition = 42% of x-40% of x=7
=> 2 % of x =7
=>2*x/100 =7
=> x= 7*100/2
=> x= 350
So total marks is 350 and pass marks is 40% of 350 =40*350/100 =140
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