In an examination, A got 20% more marks than B and B got 10% less marks than
C. If A had secured 432 marks in the exam, find the marks secured by B and by C.
Give answer If you Know Please, don't write any rubbish ans
Answers
Answer:
Let the marks obtained by B be 'x'
A/q
x + 20℅ of x = 432
x + 20/100 × x = 432
x + 1/5 × x = 432
x + x/5 = 432
(5x + x)/5 = 432
6x/5 = 432
6x = 432 × 5
x = 2160/6
x = 360 = Marks obtained by B
Again ,
Marks obtained by C be y
A/q
y - 10% of y = 360
y - 1/10 y. = 360
( 10y - y)/10 = 360
9y/10 = 360
9y = 3600
y = 3600/9
y = 400 = Marks obtained by C .
Hence , Marks obtained by B is 360
Marks obtained by C is 400
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