Math, asked by Reetinder3358, 11 months ago

In an examination A got 25% mark than B,B got 10%less than C,and C got 25%more than D.If D got 320 marks out of 500,the mark obtained by A was?

Answers

Answered by jsjeberson
5

Answer:


Step-by-step explanation:

Marks of D = 320

Marks of C = 25%+ D

                  = [(320/100) x 25] + 320

                  =80 +320

                  =400

Marks of B = C - 10%

                  = 400 - [(400/100) x 10]

                  = 400 - 40

                  = 360

Marks of A = 25%+ B

                  = [(360/100) x 25] + 360      

                  = 90 +  360

                  = 450




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