Math, asked by sanjanaagr, 3 months ago

In an examination A has scored 20 marks more than B. if B has scored 5% less marks than A , how much has B scored ?
a 360.
b 380.
c 400.
d 420.

pls explain​

Answers

Answered by rkjais1980
2

Answer:

b) 380

Step-by-step explanation:

Marks scored by A = 20 + B ——(i)

Marks scored by A = 20 + B ——(i)Marks scored by B = (100 - 5)% of A.= 95% of A

Marks scored by A = 20 + B ——(i)Marks scored by B = (100 - 5)% of A.= 95% of Aor marks scored by B = 0.95A ——(ii)

Marks scored by A = 20 + B ——(i)Marks scored by B = (100 - 5)% of A.= 95% of Aor marks scored by B = 0.95A ——(ii)Substituting 0.95 A for B in (i), we get

Marks scored by A = 20 + B ——(i)Marks scored by B = (100 - 5)% of A.= 95% of Aor marks scored by B = 0.95A ——(ii)Substituting 0.95 A for B in (i), we getMarks scored by A = 20+ 0.95A

Marks scored by A = 20 + B ——(i)Marks scored by B = (100 - 5)% of A.= 95% of Aor marks scored by B = 0.95A ——(ii)Substituting 0.95 A for B in (i), we getMarks scored by A = 20+ 0.95Aor A - 0.95A = 20

Marks scored by A = 20 + B ——(i)Marks scored by B = (100 - 5)% of A.= 95% of Aor marks scored by B = 0.95A ——(ii)Substituting 0.95 A for B in (i), we getMarks scored by A = 20+ 0.95Aor A - 0.95A = 20or 0.05 A = 20

Marks scored by A = 20 + B ——(i)Marks scored by B = (100 - 5)% of A.= 95% of Aor marks scored by B = 0.95A ——(ii)Substituting 0.95 A for B in (i), we getMarks scored by A = 20+ 0.95Aor A - 0.95A = 20or 0.05 A = 20or A = 400

Marks scored by A = 20 + B ——(i)Marks scored by B = (100 - 5)% of A.= 95% of Aor marks scored by B = 0.95A ——(ii)Substituting 0.95 A for B in (i), we getMarks scored by A = 20+ 0.95Aor A - 0.95A = 20or 0.05 A = 20or A = 400Substituting the value of A in (i), we get

Marks scored by A = 20 + B ——(i)Marks scored by B = (100 - 5)% of A.= 95% of Aor marks scored by B = 0.95A ——(ii)Substituting 0.95 A for B in (i), we getMarks scored by A = 20+ 0.95Aor A - 0.95A = 20or 0.05 A = 20or A = 400Substituting the value of A in (i), we get400 = 20 + B

Marks scored by A = 20 + B ——(i)Marks scored by B = (100 - 5)% of A.= 95% of Aor marks scored by B = 0.95A ——(ii)Substituting 0.95 A for B in (i), we getMarks scored by A = 20+ 0.95Aor A - 0.95A = 20or 0.05 A = 20or A = 400Substituting the value of A in (i), we get400 = 20 + Bor B = 400–20

Marks scored by A = 20 + B ——(i)Marks scored by B = (100 - 5)% of A.= 95% of Aor marks scored by B = 0.95A ——(ii)Substituting 0.95 A for B in (i), we getMarks scored by A = 20+ 0.95Aor A - 0.95A = 20or 0.05 A = 20or A = 400Substituting the value of A in (i), we get400 = 20 + Bor B = 400–20or B = 380

Marks scored by A = 20 + B ——(i)Marks scored by B = (100 - 5)% of A.= 95% of Aor marks scored by B = 0.95A ——(ii)Substituting 0.95 A for B in (i), we getMarks scored by A = 20+ 0.95Aor A - 0.95A = 20or 0.05 A = 20or A = 400Substituting the value of A in (i), we get400 = 20 + Bor B = 400–20or B = 380Thus the marks scored by B are 380

Similar questions