Question

In an examination A scored 40 percent and failed by 40marks,whereas B scored 60percent and got 40 marks more than the minimum number of pass marks. Find the pass marks?

Answer 1

Let Pass marks be P, and Total marks be T,

So, A got 40% therefore:

0.4T = P - 40.......(1)

B got 60%, so:

0.6T = P + 40......(2)

Solving (1) and (2), we get:

0.2T = 80, giving T = 400,

Putting value of T in (1), we get

P = 200