Question

in an examination A student get 36% mark to pass jayant get 180 mark and fail by 36 mark. find the maimum marks.

Answer 1

Let the maximum marks be a

Passing mark = 36a/100 = 9a/25

=> Jayant's marks + 36 = 9a/25

=> 180 + 36 = 9a/25

=> 216 = 9a/25

=> a = 216 × 25 / 9

=> a = 24 × 25

=> a = 600

Maximum marks = 600

Answer 2

Let the maximum marks be a

Passing mark = 36a/100 = 9a/25

=> Jayant's marks + 36 = 9a/25

=> 180 + 36 = 9a/25

=> 216 = 9a/25

=> a = 216 × 25 / 9

=> a = 24 × 25

=> a = 600

Maximum marks = 600