In an examination, a student has to secure 40% marks to pass . rahul gets 178 and fails by 32 marks . what are the maximum marks
Anonymous:
total marks 525
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The maximum mark is 525.
If the student getting pass mark is 178 + 32 = 210.
40% mark is 210. Then the 100% mark is 'X'.
To find out maximum mark is,
=> 40% of 'X' = 100%*210.
=> X = (210*100%)/40%.
=> X = 520.
Or,
If 178 marks fails by 32 marks, that means a barely-passing grade is 178 + 32 = 210 marks. We're told that the minimum passing score is 40%, so 210 is equal to 40% of the maximum marks. In other words: 210 = 0.4 x 500 = x So, the maximum score is 525.
Hope This Helps :)
If the student getting pass mark is 178 + 32 = 210.
40% mark is 210. Then the 100% mark is 'X'.
To find out maximum mark is,
=> 40% of 'X' = 100%*210.
=> X = (210*100%)/40%.
=> X = 520.
Or,
If 178 marks fails by 32 marks, that means a barely-passing grade is 178 + 32 = 210 marks. We're told that the minimum passing score is 40%, so 210 is equal to 40% of the maximum marks. In other words: 210 = 0.4 x 500 = x So, the maximum score is 525.
Hope This Helps :)
he failed by 32 marks u have written 22
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Yeah, sure, wait...
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Uh are always welcome :)
still incorrect check first line
Oh, yeah!
Now done perfectly ;)
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