Math, asked by aditi1996, 1 year ago

In an examination a student requires 40 % of the total marks to pass .If Rupa gets 185 marks and fails
by 15 marks. Find the total marks


aditi1996: nobody is there to ans my question?
SnehalD: of coarse there is,it just needs time, don't worry :)

Answers

Answered by SnehalD
69

Greetings..!

Let the maximum marks be valued as 100%.

Marks got by Rupa = 185

Marks she failed by = 15

Thus, minimum pass marks = 185 + 15 = 200

So, 40% of max marks = 200

1% of maximum marks = 200/40 = 5

Thus, max marks(100%) = 5*100 = 500

Answer : Hence, maximum marks = 500

Answered by AnIntrovert
55

\mathfrak{\large{\underline{\underline{Answer :}}}}

The total marks are 500.

\mathfrak{\large{\underline{\underline{Step-by-step\: explanation}}}}

\textsf{\underline{\underline{Given : }}}

Students needs = 40% to pass

Rula gets = 185 marks

Fails by = 15 marks

\textsf{\underline{\underline{To find :}}}

The total marks

\textsf{\underline{\underline{Solution : }}}

\textsf{Let the Total Marks be as x }

As Rula failed by 15, the marks she scored when added by 15 makes the passing marks.

\green{\boxed{\green{\boxed{\red{\sf{40\% \: of \: x = 185 + 15}}}}}}

\begin{lgathered}\begin{lgathered}\sf{\longrightarrow} \: 40\% \: of \: x = 185 + 15 \\ \\ \sf{\longrightarrow} \: \frac{40}{100} \times x = 185 + 15 \\ \\ \sf{\longrightarrow} \: \frac{40x}{100} = 200 \\ \\ \sf{\longrightarrow} \:40x = 200 \times 100 \\ \\ \sf{\longrightarrow} \:40x = 20000 \\ \\ \sf{\longrightarrow} \:x = \frac{20000}{40} \\ \\ \sf{\longrightarrow} \:x = 500\end{lgathered}\end{lgathered}

\textsf{Total Marks = 500 }

\therefore\textsf{The total marks are 500. }

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