Question

in an examination a student who scores 35% marks fails by 60 marks while another scores 52% marks got 8 marks more than the passing requirement the passing marks are​

Answer 1

This Can be solved algebraically as follows…

We assume total marks = x

1st Candidate scores 30% of x = 3x/10

Fails by 5 marks

So, minimum pass marks=( 3x/10) + 5

= (3x + 50) /10 …………(1)

2nd candidate scores 40% of x = 4x/10

He svores 10 more than minimum

=> minimum pass marks = (4x/10) - 10

= (4x-100) / 10 …………. (2)

(1)&(2) are eaqual

=> (3x+ 50)/10 = (4x- 100) / 10

=> 3x + 50 = 4x - 100

=> x = 150

=> minimum pass marks by (1)

=( 3x+50)/10

= (3 x 150 + 50) /10

=> 500/10

= 50 marks out of 150 is required to pass

So minimum pass percentage =

(50/ 150) x 100

= 100/3

= 33.3 %

ONLY AN EXAMPLE OR SIMILAR ANSWER !!1

Answer 2

Answer:

Let passing marks be P.

Also, let full marks be F.

Then,

35F/100 + 60 = P ----------(i)

And,

52F/100 = P + 8 --------(ii)

Subtracting (i) from (ii) :-

17F/100 - 60 = 8

17F/100 = 68

F = 68×100/17 = 400

Therefore, P = 35×400/100 + 60 = 140 + 60 = 200