Question

In an examination candidate a scrores 30%and fails by 40 marks while another candidate B scores 40% and gets 20 marks more than the minimum pass marks find tha maximum marks and minimum pass marks

Answer 1

Let the maximum mark be x

And minimum mark be y

30x/100=y -40

3x/10=y-40 (equation 1)

40x/100=y+20

2x/5=20+y

Y=(2x/5)-20. (Equation 2)

Substitute equation 2in equation 1

3x/10=(2x/5)-20-40

3x/10=(2x/5)-60

3x=(20x/5)-600

3x=4x-600

600=4x-3x

X=600

Therefore maximum mark is 600

Y=(2x/5)-20. From equation 2

=(1200/5)-20

=240-20

=220

Therefore pass mark is 220

Answer 2

Answer:

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