Math, asked by amarjeetkumar800012, 1 year ago

in an examination every candidate took Hindi or history or both 66% to Hindi and 59% to history the total number of a candidate was 3000 how many candidates took both Hindi and history

Answers

Answered by TooFree
3

Answer:

750 candidates took both Hindi and History


Step-by-step explanation:

Total number of Candidates = 3000


Find the number of candidates that took Hindi:

number of candidates = 66% 0f 3000

number of candidates= 0.66 x 3000 = 1980


Find the number of candidates that took History:

number of candidates = 59% 0f 3000

number of candidates= 0.59 x 3000 = 1770


Find the number of candidates that took both:

number of candidates= 1980 + 1770 - 3000 = 750


Answer: 750 candidates took both Hindi and History

Answered by abhi178
4
the number of candidate in Hindi , n(Hindi)= 66% of 3000 = 66 × 3000/100 = 66 × 30 = 1980

the number of candidate in history , n(history)= 59 % of 3000
= 59 × 3000/100 = 59 × 30 = 1770

here given, n(\text{Hindi}\cup\text{history}) = 3000

use formula, n(\text{hindi}\cup\text{history})=n(\text{Hindi})+n(\text{history})-n(\text{Hindi})\cap\text{history})

or, 3000 = 1980 + 1770 - n(\text{Hindi})\cap\text{history})

or, n(\text{Hindi})\cap\text{history}) = 1980 + 1770 - 3000 = 750

hence, number of candidate in Hindi and history = 750
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