Question

in an examination first division marks are 60% a student secures 538 marks and Misses the first division by 2 marks find the total marks of the examination

Answer 1

he has to get a minimum score of 60% in order to be in the first division.
he has missed this by 2 marks.
his score is 538.
add the 2 that he missed and he would have gotten 540.
540 = .6 * x, where x represents the total scores.
solve for x to get x = 540 / .6 = 900. 

the total marks possible are 900.
.6 * 900 = 540
that's the minimum score he required to be in the first division.
he got 538, so he's 2 short of being in the first division. 

your solution is that total marks = 900.


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