In an examination hall 350 students have to appear in English exam and 210 in mathematics exam .all the students of same subject have to be sit in the same class. If the number of students is same in all classes find the minimum number of rooms.
Answers
Answer:
Step-by-step explanation:
Given:
In an examination hall,
No. of students appearing in English exam = 350
No. of students appearing in Mathematics exam = 210
Students of the same subject have to sit in the same class
Also, no. of students is same in all classes
To find:
The minimum number of rooms.
Solution:
Firstly, we will find the maximum no. of students each room will have and to get that we will calculate the H.C.F. of 350 & 210 by prime factorisation method.
Factors of 350 & 210:
350 = 2 × 5 × 5 × 7
210 = 2 × 3 × 5 × 7
H.C.F. :
∴ H.C.F. of 350 & 210 = 2 × 5 × 7 = 70
Now, secondly, we have,
No. of students in each room = 70
and
Total no. of students appearing for both the exams = 350 + 210 = 560
∴ The required no. of rooms = =
=
Thus, the minimum no. of rooms required is 8.
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