Question

in an examination in which maximum marks where 800 A gets 15% more than B,B gets 25% more than c and c gets 10% less than D if A got 598 marks then what percentage of full marks did D get approximately

Answer 1

598-A
520-B
416-c
462-D

Answer 2

Answer:

D get 57.75%.

Step-by-step explanation:

Given : In an examination in which maximum marks where 800 A gets 15% more than B,B gets 25% more than c and c gets 10% less than D if A got 598 marks.

To find : What percentage of full marks did D get approximately?

Solution :

A gets 15% more than B

i.e, $A=\frac{115}{100}B$

B gets 25% more than C

i.e, $B=\frac{125}{100}C$

C gets 10% less than D

i.e, $C=\frac{90}{100}D$

A got 598 marks.

$598=\frac{125}{100}B$

$B=\frac{598\times 100}{115}$

$B=520$

B got 520 marks.

$520=\frac{125}{100}C$

$C=\frac{520\times 100}{125}$

$C=416$

C got 416 marks.

$416=\frac{90}{100}D$

$D=\frac{416\times 100}{90}$

$D=462$

D got 462 marks.

Into percentage - $462\times \frac{1}{800}\times 100=57.75\%$

Therefore, D get 57.75%.