Math, asked by GirishTN1627, 11 months ago

In an examination it is required to get 35% of the aggregate marks to pass. Risha got 216 marks and declared fail by 5% marks. What was the total marks?

Answers

Answered by santanudeb126
0

Answer:

720

Step-by-step explanation:

Let the total marks be =x

Risha got 35-5% marks=30% marks.

so 30% of x= 3x by 10

Atq, 3x by 10= 216

so the equation is 720..nd it is the total mrks.

Answered by sharonr
0

The total marks is 720

Solution:

Given that,

In an examination it is required to get 35% of the aggregate marks to pass

Let the total marks be "x"

Since, Risha got 216 marks and declared fail by 5% marks

Pass mark = 216 + 5 % of x

Therefore,

35 % of x =  216 + 5 % of x

\frac{35}{100} \times x = 216 + \frac{5}{100} \times x \\\\0.35x = 216+ 0.05x \\\\0.3x = 216\\\\x = 720

Thus total marks is 720

Learn more:

In an examination it is required to get 40% of the aggregate marks to pass a student get 261 marks and is declared failed by 4% marks what are the maximum aggregate marks a student can get

https://brainly.in/question/3721881

In a examination it is required to get 36 % to pass .A student gets 145 marks and fails by 35 marks . The maximum marks are?

https://brainly.in/question/1954336

Similar questions