Question

In an examination it is required to get 65% of the aggregate marks to pass. A student gets 522 marks and is declared failed by 7% marks. What are the maximum aggregate marks a student can get?

Answer 1

Answer:

Let xbe the total marks

Xx65 /l00 = 522+Xx7 / 100

65X=52200+7 X

58X=52200

x = 900 maximum marks 900

Answer 2

The maximum number is 900

Step-by-step explanation:

Let the total marks be x

Marks obtained by student =522

We are given that he is declared failed by 7% marks

So, He failed by marks = $7\%x = \frac{7}{100}x=0.07x$

So, Passing Marks = 522 +0.07x

We are given that  it is required to get 65% of the aggregate marks to pass

So, Passing marks = 65% of x = 0.65x

So, $522+0.07x=0.65x\\522=0.65x-0.07x\\522=0.58x\\\frac{522}{0.58}=x\\900=x$

Hence The maximum number is 900

#Learn more:

In an examination,a candidate scoring 360 marks less by 15 marks to score 75parsent of maximum marks. find the maximum marks.

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