Math, asked by shashwatmishra22, 5 months ago

In an examination Kiran got 27% of total marks and failed by 39. While Sri got 63% of total marks got 69 marks more than the necessary to pass the exam. What are the maximum marks?​

Answers

Answered by tparakh2012
1

Answer:

HOPE THIS HELPS!!!!

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Answered by moshnetic
0

Answer:

300

Step-by-step explanation:

Let the maximum marks of the exam be x

Kiran got 27% of total marks

So Kiran got 27% of x

So Kiran got (27 / 100) * x

So Kiran got (27x / 100)

But Kiran failed the examination by 39 marks

So he must have got 39 more marks to pass the examination

=> Marks required to pass the examination = Marks scored by Kiran + 39

= (27x / 100) + 39 ----------------> Equation 1

Sri got 63% of total marks

So Sri got 63% of x

So Sri got (63 / 100) * x

So Sri got (63x / 100)

But Sri passed the exam by 69 marks

So he has got 69 more marks than required to pass the examination

=> Marks required to pass the examination = Marks scored by Sri - 69

= (63x / 100) - 69 ----------------> Equation 2

But the passing marks is the same in both cases

=> Equation 1 = Equation 2

=> (27x / 100) + 39 = (63x / 100) - 69

=> (27x / 100) - (63x / 100) = - 69 - 39

=> (27x - 63x) / 100 = - 108

=> (- 36x) / 100 = - 108

=> - 36x = - 108 * 100

=> - 36x = - 10800

=> x = (- 10800 / - 36)

=> x = (10800 / 36)     [ Negative sign in numerator and denominator will get cancelled ]

=> x = 300

So the maximum marks in the exam is 300

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