Math, asked by kannu3221k50, 7 months ago

In an examination, Manya scores 30% and
fails by 20 marks and her friend Mahek scores
50% and gets 100 marks more than the
minimum passing marks. Find the maximum
marks and minimum marks to pass.​

Answers

Answered by rohith1975
0

Answer:

30..........................................

Step-by-step explanation:

Answered by pritujha1405
0

Let the maximum mark be x

And minimum mark be y

30x/100=y -40

3x/10=y-40 (equation 1)

40x/100=y+20

2x/5=20+y

Y=(2x/5)-20. (Equation 2)

Substitute equation 2in equation 1

3x/10=(2x/5)-20-40

3x/10=(2x/5)-60

3x=(20x/5)-600

3x=4x-600

600=4x-3x

X=600

Therefore maximum mark is 600

Y=(2x/5)-20. From equation 2

=(1200/5)-20

=240-20

=220

Therefore the pass mark is 220

Please mark it as the brainliest

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