Math, asked by himanibutta568, 6 months ago

In an examination, Nishant secured 32% marks and failed by 12 marks. Rehman secured 42% and got 28 marks more than the minimum marks required to pass. Find the maximum marks and the pass percentage of marks

Answers

Answered by Devanshpandey1678
0

Answer:

According to question,

30% of x+12=40% of x−28

100

30

x+12=

100

40

x−28

100

10

x=40⇒x=400

Passing marks =

100

30

×400+12=132

Hence, pass percentage =

400

132

×100=33%.

Answered by archi9820
2

Answer:

Let the maximum marks be x.

According to question,

30% of x+12=40% of x−28

100

30

x+12=

100

40

x−28

100

10

x=40⇒x=400

Passing marks =

100

30

×400+12=132

Hence, pass percentage =

400

132

×100=33%.

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