In an examination, Nishant secured 32% marks and failed by 12 marks. Rehman secured 42% and got 28 marks more than the minimum marks required to pass. Find the maximum marks and the pass percentage of marks
Answers
Answered by
0
Answer:
According to question,
30% of x+12=40% of x−28
⇒
100
30
x+12=
100
40
x−28
⇒
100
10
x=40⇒x=400
Passing marks =
100
30
×400+12=132
Hence, pass percentage =
400
132
×100=33%.
Answered by
2
Answer:
Let the maximum marks be x.
According to question,
30% of x+12=40% of x−28
⇒
100
30
x+12=
100
40
x−28
⇒
100
10
x=40⇒x=400
Passing marks =
100
30
×400+12=132
Hence, pass percentage =
400
132
×100=33%.
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