Question

In an examination out of hundred students 75 passed in English 60 passed in mathematics and 45 part 4 English mein protect what is the number of student passed and exactly one of the two subject

Answer 1

Step-by-step explanation:

Total no. of students =100

Total no. of students =100total no.of students passed in English =75

Total no. of students =100total no.of students passed in English =75total no.of students passed in mathematics =60

Total no. of students =100total no.of students passed in English =75total no.of students passed in mathematics =60total no. of students passed in both subject (E&M)=45

Total no. of students =100total no.of students passed in English =75total no.of students passed in mathematics =60total no. of students passed in both subject (E&M)=45 compute the students passed in exactly one of the two subject as follow:

Total no. of students =100total no.of students passed in English =75total no.of students passed in mathematics =60total no. of students passed in both subject (E&M)=45 compute the students passed in exactly one of the two subject as follow:n(E U M)= n(E)+ n (M) -n (E UM)

Total no. of students =100total no.of students passed in English =75total no.of students passed in mathematics =60total no. of students passed in both subject (E&M)=45 compute the students passed in exactly one of the two subject as follow:n(E U M)= n(E)+ n (M) -n (E UM) = 75+60-45

Total no. of students =100total no.of students passed in English =75total no.of students passed in mathematics =60total no. of students passed in both subject (E&M)=45 compute the students passed in exactly one of the two subject as follow:n(E U M)= n(E)+ n (M) -n (E UM) = 75+60-45 =135-45

Total no. of students =100total no.of students passed in English =75total no.of students passed in mathematics =60total no. of students passed in both subject (E&M)=45 compute the students passed in exactly one of the two subject as follow:n(E U M)= n(E)+ n (M) -n (E UM) = 75+60-45 =135-45 =90

Total no. of students =100total no.of students passed in English =75total no.of students passed in mathematics =60total no. of students passed in both subject (E&M)=45 compute the students passed in exactly one of the two subject as follow:n(E U M)= n(E)+ n (M) -n (E UM) = 75+60-45 =135-45 =90Thus,the number of students passed in exactly one of the two subject is 90.