Question

In an examination paul scored 10 marks more than peter and his mark were 64% of their markss were

Answer 1

Answer:

Peter scored=12.85

Paul scored=22.85

Answer 2

Answer:

Paul = 22.86 and Peter = 12.86.

Step-by-step explanation:

In an examination paul scored 10 marks more than peter.

Let the marks of paul be x.

Marks of perter = x-10

Sum of their marks = x + (x-10) = 2x-10

Paul marks were 64% of their marks.

$x=(2x-10)\times \frac{64}{100}$

$x=(2x-10)\times 0.64$

$x=1.28x-6.4$

Subtract 1.28x from both sides.

$x-1.28x=-6.4$

$-0.28x=-6.4$

Divide both sides by -0.28.

$x=\frac{-6.4}{-0.28}$

$x\approx 22.86$

The value of x is 22.86, therefore

Marks of Paul = x = 22.86

Marks of perter = 22.86-10 = 12.86