Math, asked by nanduchowdary177, 5 months ago

in an examination Paul scored 15 Mark's and his Mark's were 75% of sum of their Mark's. calculate the Mark's obtained by paul​

Answers

Answered by Helpingbot
0

Answer:

Paul = 22.86 and Peter = 12.86.

Step-by-step explanation:

In an examination paul scored 10 marks more than Mark.

Let the marks of paul be x.

Marks of Mark = x-10

Sum of their marks = x + (x-10) = 2x-10

Paul marks were 64% of their marks.

x=(2x-10)\times \frac{64}{100}

x=(2x-10)\times 0.64

x=1.28x-6.4

Subtract 1.28x from both sides.

x-1.28x=-6.4

-0.28x=-6.4

Divide both sides by -0.28.

x=\frac{-6.4}{-0.28}

x\approx 22.86

The value of x is 22.86, therefore

Marks of Paul = x = 22.86

Marks of Mark = 22.86-10 = 12.86

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