in an examination Paul scored 15 Mark's and his Mark's were 75% of sum of their Mark's. calculate the Mark's obtained by paul
Answers
Answered by
0
Answer:
Paul = 22.86 and Peter = 12.86.
Step-by-step explanation:
In an examination paul scored 10 marks more than Mark.
Let the marks of paul be x.
Marks of Mark = x-10
Sum of their marks = x + (x-10) = 2x-10
Paul marks were 64% of their marks.
x=(2x-10)\times \frac{64}{100}
x=(2x-10)\times 0.64
x=1.28x-6.4
Subtract 1.28x from both sides.
x-1.28x=-6.4
-0.28x=-6.4
Divide both sides by -0.28.
x=\frac{-6.4}{-0.28}
x\approx 22.86
The value of x is 22.86, therefore
Marks of Paul = x = 22.86
Marks of Mark = 22.86-10 = 12.86
______________________________________________________
Pls mark as THE BRAINLIEST
_______________________________________________________
Similar questions
Computer Science,
2 months ago
Computer Science,
2 months ago
Math,
10 months ago
India Languages,
10 months ago