In an examination, ratio of passes to failures is 8:1. If 10 less had appeared and 30 more had passed the ratio would have been 15:1. How many students had appeared for the examination?
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Answered by
23
Answer:
810
Step-by-step explanation:
Let, no. of students passed = 8x
So, students failed = x
Now, total students = 8x + x = 9x
ATQ, case-2
Total students = 9x - 10
Passed = 8x + 30
Fail = ( 9x - 10 ) - ( 8x + 30 ) = x - 40
Now, ( 8x + 30 ) / ( x - 40 ) = 15 / 1
8x + 30 = 15x - 600
7x = 630
x = 90
9x = 810
Answered by
1
Answer:
hi dear it's your answer...
Step-by-step explanation:
hope it helps mainly the 10 th class students of icse
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