Question

In
an examination,
the
number
of
students
who
passed and the
number of students
who failed were in
the ratio 25 : 4. If five
more students had
appeared and
and the
number of failures
was two less than
the earlier, the ratio
of
passers to failures
would have been
22:3. The number
of
students
who
the
appeared in
examination, is​

Answer 1

Step-by-step explanation:

early ratio :- 25:4

so the no. of students passed be =25x

failed be =4x

total no. of students appear be =29x

new...no. of candidates..appeared is 29x+5

new no. of failures=4x-2

new no. of passed be

$(29x + 5) - (4x - 2)$

$29x + 5 - 4x + 2 \\ 25x + 7$

given new ratio of passed and failed....is..22:3

$\frac{(25x + 7)}{(4x - 2)} = \frac{22}{3}$

cross multiply,

$3(25x + 7) = 22(4x - 2) \\ = > 75x + 21 = 88x - 44$

$= > 75x - 88x = - 44 - 21 \\ - 13x = - 65$

$x = \frac{ - 65}{ - 13} \\ - and - gets \: ancelled \\ x = \frac{65}{13} \\ x = 5$

$total \: no. \: of \: students \: appeared = 29x \\ 29(5) \\ = > 145$

therefore ur answer is 145

hope it's helpful....

stay home#stay safe

Answer 2

Answer:

Total number of students who appeared in the examination is 145

Step-by-step explanation:

Refer to the attachment for step by step explanation