In an examination , the number of those that passed and the number of those that failed were in the ratio 3:1.Had 8 more appeared, and 6 less passed, the of passes to failures would have been 2:1.Find how many appeared?i need full explanation
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let the pass student a & fail student b
a/b=3/1
total student a+b
if 6 more appeared
total student a+b+6
then pass student less by 6=a-6
a-6/b+12=2
a-6=2b+24
3b-6=2b+24
b=30
a=90
120-answer
a/b=3/1
total student a+b
if 6 more appeared
total student a+b+6
then pass student less by 6=a-6
a-6/b+12=2
a-6=2b+24
3b-6=2b+24
b=30
a=90
120-answer
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