Question

In an examination, the number of those that passed nd the number of those that failed
were in the ratio 3: 1. Had 8 more appeared, and 6 less passed, the ratio of passed to
failures would have been 2:1. Find how many appeared ?​

Answer 1

let passed student =3x and failed =x

total = 4x

if 8 more appeared then 4x+8

6 less passed then 3x-6

total student failed= total student appeared- total student passed

(4x+8)-(3x-6)= x+14

ratio of passed : failed = 2:1

(4x+8)/(3x-6)=2:1

3x-6=2x+28

x=34

total appeared = 4x =4×34=136

Answer 2

Answer:

total students were 34

Step-by-step explanation:

the ratio of passed students by failed students= 3:1

therefore in total there are (3x+x) students

as per the question

if (3x+x) +8 be the total students

and if 3x - 6 had passed

then the ratio of passed students by failed students would have been (2x+x)

if an equation is derived it would been

(3x-6)/{(3x+x)+8} - (3x-6)= 2/1

passed /total students - passed =2/1

3x-6=(3x+x+8-3x+6)×2

3x-6=2x+28

x=34