Question

In an examination, the number of those who passed and the number of those who failed were in the ratio 4 : 1. If 35 less had appeared and the number of failures were 9 more than earlier, the ratio of students who passed to the number of students who failed would have been 2 : 1. Find the total number of those who appeared at the examination.

Answer 1

Please see the attachment

Answer 2

The total number of students are 155.

Step-by-step explanation:

Consider the provided information.

the number of those who passed and the number of those who failed were in the ratio 4 : 1.

Let the number of failed students be x

The Number of passed students = 4x  

The total number of students was 5x .

If 35 less had appeared and the number of failures were 9 more than earlier,

If total number of students be 5x – 35

number of failed students  = x + 9

passed students = (5x – 35)–(x + 9)= 4x–44

The ratio of students who passed to the number of students who failed would have been 2 : 1.

$\frac{4x-44}{x + 9}=\frac{2}{1}$

$4x-44=2x + 18$

$2x=62$

$x=31$

The total number of students are 5x=5×31=155

Hence, the total number of students are 155.

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