in an examination the pass marks is 40℅. if a candidate gets 65 marks and fails by 3 marks find the maximum marks
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passing marks=65+3=68
passing marks in %=40%
so,40%of x=68
x=the total marks =170
passing marks in %=40%
so,40%of x=68
x=the total marks =170
Answered by
1
let's assume that the maximum marks be "M".
As it is given that the student got 65 marks and still failed by 3 marks that means that passing marks is
65+3=68
so 68 is 40%of the maximum marks
(40/100)xM=68
M=(68x100)/40 =170
So, the maximum marks was 170
As it is given that the student got 65 marks and still failed by 3 marks that means that passing marks is
65+3=68
so 68 is 40%of the maximum marks
(40/100)xM=68
M=(68x100)/40 =170
So, the maximum marks was 170
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