Question

In an examnation ,5% of the applicants were found ineligible and 85% of the eligible candidates belonged to the general category. If 4275 candidates belonged to other cateories, then how many candidates applied for the examination ?

Answer 1

Let the total number of candidates candidates be x

5/100 * x + 85/100 * x + 4275 = x

On solving,

x/20 + 17x/20 + 4275 = x

18x/20 + 4275 =  x

9x/10 + 42750/10 = x

(9x + 42750)/10  = x

9x + 42750 = x * 10

10x = 9x + 42750

10x - 9x = 42750

x = 42750

So, 42750 candidates applied for the examination.

Alternatively,

5% + 85% = 90% of the candidates belong to general category.

So 100 - 90 = 10% people belong to other categories

10% of x = 4275

10/100 * x = 4275

x/10 = 4275

x = 4275 * 10 = 42750

Answer 2

let the total candidate who applied for the examination was 100%

ineligible candidates = 5 %

eligible candidates = 100 - 5 = 95 %

General category candidates:
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= 85 % of 95

= 0.85 × 95 = 80.75 %

Other category candidates:
-----–--------------------------------
= 95 - 80.75 = 14.25 %

according to the given statement :

Other category candidate = 4275

14.25 % = 4275

1% = 300

100 % = 30,000

therefore, the candidates who applied for the examination was 30,000.

Answer : applicants = 30,000

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