Math, asked by prince358375, 3 months ago

In
an exhibition the cost of tickets for on adult
is of Rs 5 more then thrice the cost of ticket
for a child, which equation relates the cost y of
adult ticket in term of the cost,
x
of child ticket?
y= 5+ 3x
y+5= 3x
y= 3 + 5x
Y+ 3 = 5x​

Answers

Answered by dualadmire
1

The relation between the cost of an adult and child ticket is (1) y = 5 + 3x

Given: The cost of tickets for 1 adult ticket is Rs 5 more than thrice the cost of a ticket for a child.

The cost of 1 adult ticket = y

The cost of 1 child ticket = x

To Find: The relation between the cost of adult and child tickets.

Solution:

This is a language-based question and we need to proceed as the language suggests in the question.

We are given that,

The cost of 1 adult ticket = y

The cost of 1 child ticket = x,

Thrice the cost of a ticket for a child = Rs. 3x

Rs 5 more than thrice the cost of a ticket for a child means = Rs. ( 5 + 3x )

Now this is equal to the cost of 1 ticket for an adult = Rs. y

Equating both we get,

               y = 5 + 3x

Hence,

The relation between the cost of an adult and child tickets is (1) y = 5 + 3x

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Answered by brainlysme8
0

A. y = 5 + 3x

Explanation:

Let the cost of ticket of a child = x

Let the cost of ticket of an adult = y

Given,

The cost of ticket of an adult is 5 more than thrice the cost of ticket of a child.

Thrice the cost of ticket of a child = 3 (x) = 3x

5 more than thrice the cost of ticket of a child = 3x + 5

Therefore, y = 5 + 3x

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