Question

in an exmination a student gets 32% marks adn fails by 20 marks . another student gets 42% marks and gets 30 makrs more than the minimum pass marks. find the maximum marks and the pass perentage.

Answer 1

Step-by-step explanation:

Let the maximum mark be x

ATQ,

32% of x+20 = 42% of x-30

32x/100+20=42x/100-30

32x/100-42x/100=-30-20

-10x/100=-50

x=-50×100/-10

=-5000/-10

=500

Answer 2

Answer:

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