In an experiment, 200 V A.C. is applied at the ends of an
LCR circuit. The circuit consists of an inductive reactance
(XL ) = 50 ????, capacitive reactance (XC ) = 50 ???? and ohmic
resistance (R) = 10 W. The impedance of the circuit is
(a) 10???? (b) 20???? (c) 30???? (d) 40????
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The impedance of L-C-R circuit is
Z=
(X
L
−X
C
)
2
+R
2
=
(50−50)
2
+(10)
2
=10Ω
Now the rms current flowing in the circuit is
ie
Z
E
=
10
200
=20amp
The potential difference across the inductance is
V
L
=IX
L
=20×50×=1000V,V
R
=iR=20×10=200V
The potential difference across L-C is (50−50)×20=0
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