Physics, asked by shahisthakhan5105, 9 months ago

In an experiment, 200 V A.C. is applied at the ends of an
LCR circuit. The circuit consists of an inductive reactance
(XL ) = 50 ????, capacitive reactance (XC ) = 50 ???? and ohmic
resistance (R) = 10 W. The impedance of the circuit is
(a) 10???? (b) 20???? (c) 30???? (d) 40????

Answers

Answered by namisha7
0

Answer:

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The impedance of L-C-R circuit is

Z=

(X

L

−X

C

)

2

+R

2

=

(50−50)

2

+(10)

2

=10Ω

Now the rms current flowing in the circuit is

ie

Z

E

=

10

200

=20amp

The potential difference across the inductance is

V

L

=IX

L

=20×50×=1000V,V

R

=iR=20×10=200V

The potential difference across L-C is (50−50)×20=0

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