Question

In an experiment, 200V A.C. is applied at the ends
of an LCR circuit. The circuit consists of an
inductive reactance (Xᴌ) = 50Ω , capacitive
reactance (Xᴄ) = 50Ω and ohmic resistance
(R) = 10Ω. The impedance of the circuit is
(a) 10Ω (b) 20Ω
(c) 30Ω (d) 40Ω

Answer 1

Answer:

The impedance of L-C-R circuit is

The impedance of L-C-R circuit is$$Z=\sqrt { { \left( { X }_{ L }-{ X }_{ C } \right)  }^{ 2 }+{ R }^{ 2 } } =\sqrt { { \left( 50-50 \right)  }^{ 2 }+{ \left( 10 \right)  }^{ 2 } } =10\Omega $$

Now the rms current flowing in the circuit is

Now the rms current flowing in the circuit isie E/Z=200/10=20amp

The potential difference across the inductance is

The potential difference across the inductance isVL=IXL=20×50×=1000V,

VR=iR=20×10=200V

The potential difference across L-C

is (50−50)×20=0