Question

In an experiment 4 gm of M2Ox oxide was reduced to 2.8 gram of the metal is atomic mass of the metal is 56 grams the number of atoms in the oxide is

Answer 1

From mole concept 2 we get,
Moles of M * x = Moles of M* x
Hence,
moles of M = 4*2/(2*56 + 16x)
that is equals to => 2.8 / 56
Therefore,
8/(16x + 112) = 1/20
160 = 16x + 112
16x = 58
x = 58/16
Moles of O atoms => 4/(112 + 16*58/16)*58/16
No. of atoms = > 0.0852 * 6.023 x 10^23 atoms = > 0.513 x 10^23 atoms.