In an experiment, 4g of H2 reacts with 32g of O2to produce 36g of H2O. Calculate the amount of O2 required to react with 12g of H2 to produce 108g of H2O.
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Answer:
22.5gm
Explanation:
H
2
+
2
1
O
2
⟶H
2
O
Mass-4g20g
Moles-20.625
1 mole of H
2
requires 0.5 moles of O
2
.
∴ 1.25 moles of H
2
requires 0.625 moles of O
2
∴ O
2
is a limiting reagent.
0.5 mole O
2
⟶1 mole H
2
O
∴0.625 mole O
2
=
0.5
1×0.625
moles H
2
O.
=1.25 moles of H
2
O
Therefore, mass of H
2
O formed =1.25×18=22.5 gm
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