Question

In an experiment, 4g of M2Ox oxide was reduced to 2.8g of the metal. If the atomic mass of the metal is 56 g mol^-1, the number of O atoms in the oxide is (A) 1(B) 2 (C) 3(D) 4

Answer 1

$\huge\underline\green{\sf Answer}$

$\large{\boxed{\sf (C)3}}$

$\huge\underline\green{\sf Solution}$

$\large{\sf 1\:mole\:M_{2}O_{x}=(2×56+16x)g}$

$\large{\sf Now (2×56+16x)of\:oxide\:Of\:metal=112g}$

Therefore ,

$\large{\sf 4g\:of\:oxide\:metal={\frac{112×4}{112}}+16x}$

$\large{\sf But\:112×{\frac{4}{112}}+16x=2.8(given)}$

$\huge\red{\boxed{\sf x =3}}$