In an experiment 5.0 g of CaCO3 on heating gave 2.8 g CaO and 2.2 g v CO2. Show that these results are in accordance with the law of conservation of mass.
Answers
Answered by
1
Answer:
They are
Explanation:
First The mass is intact so thats good
next
Ca CO3 has 1 Ca 1 C and 3 O and the result has the same therefore its correct
Answered by
1
Answer:
given -
5.0 g of CaCO3
gives 2.8 gram of cao and 2.2 grams of co2
Explanation:
caco3---->CaO + co2
now,
according to law of conservation of mass
mass can neither be created nor be destroyed
so
mass of reactant= 5.0 g
mass of product = mass of co2 + mass of cao= 2.8 g + 2.2g = 5.0 g
thus ,
maSS OF REACTANTS IS EQUA;LL TO MASS OF PRODUCTS
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