Question

In an experiment 5.0 g of CaCO3 on heating gave 2.8 g CaO and 2.2 g v CO2. Show that these results are in accordance with the law of conservation of mass.​

Answer 1

Answer:

They are

Explanation:

First The mass is intact so thats good

next

Ca CO3 has 1 Ca 1 C and 3 O and the result has the same therefore its correct

Answer 2

Answer:

given -

5.0 g of CaCO3

gives 2.8 gram of cao and 2.2 grams of co2

Explanation:

caco3---->CaO + co2

now,

according to law of conservation of mass

mass can neither be created nor be destroyed

so

mass of reactant= 5.0 g

mass of product = mass of co2 + mass of cao= 2.8 g + 2.2g = 5.0 g

thus ,

maSS OF REACTANTS IS EQUA;LL TO MASS OF PRODUCTS

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